1/2(2x-3)^2+1=11

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Solution for 1/2(2x-3)^2+1=11 equation:


x in (-oo:+oo)

(1/2)*(2*x-3)^2+1 = 11 // - 11

(1/2)*(2*x-3)^2-11+1 = 0

1/2*(2*x-3)^2-11+1 = 0

1/2*(2*x-3)^2-11+1 = 0

2*x^2-6*x-13/2+1 = 0

2*x^2-6*x-11/2 = 0

2*x^2-6*x-11/2 = 0

2*x^2-6*x-11/2 = 0

DELTA = (-6)^2-(-11/2*2*4)

DELTA = 80

DELTA > 0

x = (80^(1/2)+6)/(2*2) or x = (6-80^(1/2))/(2*2)

x = (4*5^(1/2)+6)/4 or x = (6-4*5^(1/2))/4

(x-((6-4*5^(1/2))/4))*(x-((4*5^(1/2)+6)/4)) = 0

(x-((6-4*5^(1/2))/4))*(x-((4*5^(1/2)+6)/4)) = 0

( x-((4*5^(1/2)+6)/4) )

x-((4*5^(1/2)+6)/4) = 0 // + (4*5^(1/2)+6)/4

x = (4*5^(1/2)+6)/4

( x-((6-4*5^(1/2))/4) )

x-((6-4*5^(1/2))/4) = 0 // + (6-4*5^(1/2))/4

x = (6-4*5^(1/2))/4

x in { (4*5^(1/2)+6)/4, (6-4*5^(1/2))/4 }

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